A quick solution to OrderedDict’s limitations in Python with O(1) index lookups

Background to the Problem

I work regularly with gigantic machine learning datasets. One very versatile format, for use in WEKA is the “ARFF” (Attribute Relation File Format). This essentially creates a nicely structured, rich CSV file which can easily be used in Logistic Regression, Decision Trees, SVMs etc. In order to solve the problem of very sparse CSV data, there is a sparse ARFF format that lets users convert sparse lines in each file such as:

f0 f1 f2 f3 fn
1 0 1 0 0

Into a more succint version where you have a list of features and simply specify the feature’s index and value (if any):


{0 1, 2 1}

i.e. {feature-index-zero is 1, feature-index-two is 1}, simply omitting all the zero-values.

The Implementation Problem

This is easy enough if you have, say 4 features, but what if you have over 1 million features and need to find the index of each one? Searching for a feature in a list is O(n), and if your training data is huge too, then creating the sparse ARFF is going to be hugely inefficient:

I thought I could improve this by using an OrderedDict. This is, very simply, a dictionary that maintains the order of its items – so you can pop() items from the end in a stack-like manner. However, after some research on StackOverflow, this disappointingly this doesn’t contain any efficient way to calculate the index of key:

The solution

What can we do about this? Enter my favorite thing ever, defaultdicts with lambdas:

Assigning items values in addition to the index is fairly straightforward with a slightly modified lambda:


This is a fun fix, but doesn’t support full dictionary functionality – deleting items won’t reorder the index and you can’t iterate in order through this easily. However, since in creating this ARFF file, there’s no need for deletions or iteration that’s not a problem.

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